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Fixes #333
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#' Estimate Burr Parameters | ||
#' | ||
#' @family Parameter Estimation | ||
#' @family Burr | ||
#' | ||
#' @author Steven P. Sanderson II, MPH | ||
#' | ||
#' @details This function will see if the given vector `.x` is a numeric vector. | ||
#' It will attempt to estimate the prob parameter of a Burr distribution. | ||
#' | ||
#' @description This function will attempt to estimate the Burr prob parameter | ||
#' given some vector of values `.x`. The function will return a list output by default, | ||
#' and if the parameter `.auto_gen_empirical` is set to `TRUE` then the empirical | ||
#' data given to the parameter `.x` will be run through the `tidy_empirical()` | ||
#' function and combined with the estimated Burr data. | ||
#' | ||
#' @param .x The vector of data to be passed to the function. Must be non-negative | ||
#' integers. | ||
#' @param .auto_gen_empirical This is a boolean value of TRUE/FALSE with default | ||
#' set to TRUE. This will automatically create the `tidy_empirical()` output | ||
#' for the `.x` parameter and use the `tidy_combine_distributions()`. The user | ||
#' can then plot out the data using `$combined_data_tbl` from the function output. | ||
#' | ||
#' @examples | ||
#' library(dplyr) | ||
#' library(ggplot2) | ||
#' | ||
#' tb <- tidy_burr(.shape1 = 1, .shape2 = 2, .rate = .3) %>% pull(y) | ||
#' output <- util_burr_param_estimate(tb) | ||
#' | ||
#' output$parameter_tbl | ||
#' | ||
#' output$combined_data_tbl %>% | ||
#' tidy_combined_autoplot() | ||
#' | ||
#' @return | ||
#' A tibble/list | ||
#' | ||
#' @export | ||
#' | ||
|
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util_burr_param_estimate <- function(.x, .auto_gen_empirical = TRUE) { | ||
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# Tidyeval ---- | ||
x_term <- as.numeric(.x) | ||
n <- length(x_term) | ||
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# Checks ---- | ||
if (!is.vector(x_term, mode = "numeric")) { | ||
rlang::abort( | ||
message = "The '.x' term must be a numeric vector.", | ||
use_cli_format = TRUE | ||
) | ||
} | ||
|
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if (any(x_term < 0)) { | ||
rlang::abort( | ||
message = "All values of 'x' must be non-negative integers greater than 0.", | ||
use_cli_format = TRUE | ||
) | ||
} | ||
|
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if (n < 2) { | ||
rlang::abort( | ||
message = "You must supply at least two data points for this function.", | ||
use_cli_format = TRUE | ||
) | ||
} | ||
|
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# Parameters ---- | ||
# https://stats.stackexchange.com/a/595379/35448 | ||
burr_lik <- function(theta,x){ | ||
c <- exp(theta[1]) | ||
k <- exp(theta[2]) | ||
mu <- 0 | ||
sigma <- exp(theta[3]) | ||
bll <- actuar::dburr(x, c, k, mu, sigma) | ||
return(-sum(log(bll))) | ||
} | ||
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brmod <- optim( | ||
c( | ||
.shape1 = 0, | ||
.shape2 = 0, | ||
.scale = 0 | ||
), | ||
fn = burr_lik, | ||
x = x_term | ||
) | ||
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est_params <- exp(brmod$par) | ||
shape1 <- est_params[[1]] | ||
shape2 <- est_params[[2]] | ||
rate <- est_params[[3]] | ||
scale <- 1/rate | ||
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# Return Tibble ---- | ||
if (.auto_gen_empirical) { | ||
te <- tidy_empirical(.x = x_term) | ||
td <- tidy_burr(.n = n, .shape1 = round(shape1, 3), | ||
.shape2 = round(shape2, 3), | ||
.rate = round(rate, 3)) | ||
combined_tbl <- tidy_combine_distributions(te, td) | ||
} | ||
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ret <- dplyr::tibble( | ||
dist_type = "Burr", | ||
samp_size = n, | ||
min = min(x_term), | ||
max = max(x_term), | ||
mean = mean(x_term), | ||
shape1 = shape1, | ||
shape2 = shape2, | ||
rate = rate, | ||
scale = scale | ||
) | ||
|
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# Return ---- | ||
attr(ret, "tibble_type") <- "parameter_estimation" | ||
attr(ret, "family") <- "bernoulli" | ||
attr(ret, "x_term") <- .x | ||
attr(ret, "n") <- n | ||
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if (.auto_gen_empirical) { | ||
output <- list( | ||
combined_data_tbl = combined_tbl, | ||
parameter_tbl = ret | ||
) | ||
} else { | ||
output <- list( | ||
parameter_tbl = ret | ||
) | ||
} | ||
|
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return(output) | ||
} |
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