Fix an incorrect autocorrect for Style/MultipleComparison when statement with more comparisons precedes a statement with less comparisons

[fatkodima]

I caught an edge case for Style/MultipleComparison cop, when we have an expression with more comparisons that is followed by an expression with less comparisons.

x = 1
x == 1 || x == 2 || x == 3  # <=== more comparisons
x == 1 || x == 2            # <=== less comparisons

Is corrected to

x = 1
[1, 2, 3].include?(x)
[1, 2, 3, 1, 2, 3, 1, 2].include?(x)

But should be

x = 1
[1, 2, 3].include?(x)
[1, 2].include?(x)

[bbatsov]

Nice catch!