Sanitize escape char in Transformer::transformSymbolicName

Escaped symbol name from parser will be of
form "`Some.Value`". Therefore, we need to sanitize
it such that we don't store the symbol with
escape character.

src/include/parser/transformer.h

@@ -16,6 +16,8 @@ class Transformer {
     std::unique_ptr<Statement> transform();
 
 private:
+    static constexpr std::string_view ESCAPE_SYMBOL_CHAR = "`";
+
     std::unique_ptr<RegularQuery> transformQuery(CypherParser::OC_QueryContext& ctx);
 
     std::unique_ptr<RegularQuery> transformRegularQuery(CypherParser::OC_RegularQueryContext& ctx);

src/parser/transformer.cpp

@@ -914,7 +914,14 @@ std::string Transformer::transformSymbolicName(CypherParser::OC_SymbolicNameCont
     if (ctx.UnescapedSymbolicName()) {
         return ctx.UnescapedSymbolicName()->getText();
     } else if (ctx.EscapedSymbolicName()) {
-        return ctx.EscapedSymbolicName()->getText();
+        std::string escapedSymbolName = ctx.EscapedSymbolicName()->getText();
+        // escapedSymbolName symbol will be of form "`Some.Value`". Therefore, we need to sanitize
+        // it such that we don't store the symbol with escape character.
+        if (escapedSymbolName.starts_with(ESCAPE_SYMBOL_CHAR) &
+            escapedSymbolName.ends_with(ESCAPE_SYMBOL_CHAR)) {
+            escapedSymbolName = escapedSymbolName.substr(1, escapedSymbolName.size() - 2);
+        }
+        return escapedSymbolName;
     } else {
         assert(ctx.HexLetter());
         return ctx.HexLetter()->getText();