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W10_PA1.py
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W10_PA1.py
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# You are provided with a number D containing only digits 0's and 1's.
# Your aim is to convert this number to have all the digits same.
# For that, you will change exactly one digit i.e. from 0 to 1 or from 1 to 0.
# If it is possible to make all digits equal (either all 0's or all 1's) by flipping exactly 1 digit
# then output "YES", else print "NO" (quotes for clarity).
# Input Format:
# The first line of the input contains the number D made of only digits 1's and 0's.
# Output:
# Print 'YES' or 'NO' depending on whether its possible to make it all 0s or 1s or not.
# Example-1:
# Input:
# 101
# Output:
# YES
# Example-2:
# Input:
# 11
# Output:
# NO
# Explanation:
# In the first example, it is possible to make all the digits same by flipping the middle digit from 0 to 1.
# In the second example it is not possible.
# ----------------------------------------------------------------------------------------------------------
# Take input in String.
s = input()
# Counter : For counting number of 0's and 1's in String.
count0 = 0
count1 = 0
# For checking each index in String if equal to 0 or 1.
# And incrementing counters.
for i in range(0, len(s)):
if s[i] == "1":
count1 += 1
if s[i] == "0":
count0 += 1
# Checking condition if less than 2 or not.
if count0 < 2 or count1 < 2:
print("YES", end="")
else:
print("NO", end="")