Response implementation of Deserialize is not general enough

[aniketfuryrocks]

@niklasad1 I am porting tests here

with jsonrpc

https://github.com/blockworks-foundation/solana/blob/bd782634dcd39d267381a55e7a8c5d52ab314292/rpc/src/rpc.rs#L5914

now

    let expected = serde_json::json!({
        "jsonrpc":"2.0",
        "error": {
            "code": -32003,
            "message": "Transaction signature verification failure"
        },
        "id":1
    });

    let value: jsonrpsee::types::Response<()> = serde_json::from_value(expected).unwrap();

    println!("{:?}", value.to_string());

error

error: implementation of `Deserialize` is not general enough
  --> src/main.rs:54:49
   |
54 |     let value: jsonrpsee::types::Response<()> = serde_json::from_value(expected).unwrap();
   |                                                 ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ implementation of `Deserialize` is not general enough
   |
   = note: `Deserialize<'0>` would have to be implemented for the type `Response<'_, ()>`, for any lifetime `'0`...
   = note: ...but `Deserialize<'1>` is actually implemented for the type `Response<'1, ()>`, for some specific lifetime `'1`

error: could not compile `rpc_` due to previous error

[niklasad1]

The simple fix is to do:

let expected = r#"{"jsonrpc":"2.0", "error": { "code": -32003, "message": "Transaction signature verification failure"},"id":1}"#
let value: jsonrpsee::types::Response<()> = serde_json::from_str(expected).unwrap();

I think that value must be borrowed in the Response<'a, T> and from_value moves that value and won't work.

You could open an issue for this as this is too complicated to get right but ideally you shouldn't need to use/allocate serde_json::Value in jsonrpsee as we are using serde_json::value::RawValue internally