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Does not provide a public link to the file #80

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LilBtr opened this issue Apr 11, 2022 · 1 comment

LilBtr commented Apr 11, 2022

The second line of this code did not display a link in the terminal

m.get_upload_link(file)

N4GR commented Jun 7, 2022 •

edited

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Hey,
Super late response and hopefully you've sorted it out yourself, have you tried this?

You need to assign it to a variable and then print the variable to display it in console:

file = m.upload('path_to_file')
linkname = m.get_upload_link(file)

print (linkname)

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