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Why an Option type instead of type
| undefined?
#87
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I looked more into it, as For |
probably because Option handles |
Then you can just expand the union to |
It abstracts the absence of a given type T. You could think of it as just an alias for type representation in raw typescript: T|null|undefined, but there's little more about it. BTW, I understand there are some issues with functions that take options as arguments are easy to cause an error, since the type signature says it takes option type(which should be T| null | undefined), but only works properly when it takes |
Hey, this is a question instead of a real issue, but the discussion tab isnt present.
So I am wondering why you use an
Option
-Type instead of simply using a union type of<provided type> | undefined
?Because with the specific type you always need to wrap the value first instead of just using the functions.
I am not saying that one is better than the other, but simply curious :D
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