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860. Lemonade Change

At a lemonade stand, each lemonade costs $5.

Customers are standing in a queue to buy from you, and order one at a time (in the order specified by bills).

Each customer will only buy one lemonade and pay with either a $5, $10, or $20 bill. You must provide the correct change to each customer, so that the net transaction is that the customer pays $5.

Note that you don't have any change in hand at first.

Return true if and only if you can provide every customer with correct change.

Example 1:

Input: [5,5,5,10,20]
Output: true
Explanation:
From the first 3 customers, we collect three $5 bills in order.
From the fourth customer, we collect a $10 bill and give back a $5.
From the fifth customer, we give a $10 bill and a $5 bill.
Since all customers got correct change, we output true.

Example 2:

Input: [5,5,10]
Output: true

Example 3:

Input: [10,10]
Output: false

Example 4:

Input: [5,5,10,10,20]
Output: false
Explanation:
From the first two customers in order, we collect two $5 bills.
For the next two customers in order, we collect a $10 bill and give back a $5 bill.
For the last customer, we can't give change of $15 back because we only have two $10 bills.
Since not every customer received correct change, the answer is false.

Note:

  • 0 <= bills.length <= 10000
  • bills[i] will be either 5, 10, or 20.

Solutions (Rust)

1. Simulation

impl Solution {
    pub fn lemonade_change(bills: Vec<i32>) -> bool {
        let mut five = 0;
        let mut ten = 0;
        for bill in bills {
            if bill == 5 {
                five += 1;
            } else if bill == 10 {
                ten += 1;
                five -= 1;
            } else if ten > 0 {
                ten -= 1;
                five -= 1;
            } else {
                five -= 3;
            }

            if five < 0 {
                return false;
            }
        }

        true
    }
}