reverseFizzBuzz.md

FizzBuzz Backwards

• Traditionally in FizzBuzz, multiples of 3 are replaced by "Fizz" and multiples of 5 are replaced by "Buzz". But we could also play FizzBuzz with any other integer pair [n, m] whose multiples are replaced with Fizz and Buzz.

• For a sequence of numbers, Fizzes, Buzzes and FizzBuzzes, find the numbers whose multiples are being replaced by Fizz and Buzz. Return them as an array [n, m]

• The Fizz and Buzz numbers will always be integers between 1 and 50, and the sequence will have a maximum length of 100. The Fizz and Buzz numbers might be equal, and might be equal to 1.

Examples:

• Classic FizzBuzz; multiples of 3 are replaced by Fizz, multiples of 5 are replaced by Buzz:

[1, 2, "Fizz", 4, "Buzz", 6] ==> [3, 5]

• Multiples of 2 are replaced by Fizz, multiples of 3 are replaced by Buzz:

[1, "Fizz", "Buzz", "Fizz", 5, "FizzBuzz"] ==> [2, 3]

• Multiples of 2 are replaced by Fizz and Buzz:

[1, "FizzBuzz", 3, "FizzBuzz", 5, "FizzBuzz"] ==> [2, 2]

• Fizz = 1, Buzz = 6:

["Fizz", "Fizz", "Fizz", "Fizz", "Fizz", "FizzBuzz"] ==> [1, 6]

Solution:

function reverseFizzBuzz(array) {
  let fizz = array.indexOf("Fizz") + 1
  let buzz = array.indexOf("Buzz") + 1
  
  if(fizz === 0){
    fizz = array.indexOf("FizzBuzz") + 1
  } if (buzz === 0){
    buzz = array.indexOf("FizzBuzz") + 1
  }
  return [fizz, buzz]
};

console.log(reverseFizzBuzz([1,2,"Fizz",4,"Buzz"])); // [3,5]
console.log(reverseFizzBuzz([1,"Fizz","Buzz","Fizz",5,"FizzBuzz"])); // [2,3]
console.log(reverseFizzBuzz([1,"FizzBuzz",3,"FizzBuzz",5,"FizzBuzz"])); // [2,2]