为什么prinf中不能使用\n

[21mw12]

请求格式是以下：

{
    "cmd": [{
        "args": ["/usr/bin/gcc", "a.c", "-o", "a"],
        "env": ["PATH=/usr/bin:/bin"],
        "files": [{
            "content": ""
        }, {
            "name": "stdout",
            "max": 10240
        }, {
            "name": "stderr",
            "max": 10240
        }],
        "cpuLimit": 10000000000,
        "memoryLimit": 104857600,
        "procLimit": 50,
        "copyIn": {
            "a.c": {
                "content": "#include <stdio.h>\nint main() {\nint a, b, sum;\nscanf(\"%d %d\", &a, &b);\nsum = a + b;\nprintf(\"%d\n\", sum);\nreturn 0;\n}"
            }
        },
        "copyOut": ["stdout", "stderr"],
        "copyOutCached": ["a"]
    }]
}

服务器端则会返回以下内容：

[
    {
        "status": "Nonzero Exit Status",
        "exitStatus": 1,
        "time": 12159186,
        "memory": 3538944,
        "runTime": 12586787,
        "files": {
            "stderr": "a.c: In function 'main':\na.c:6:8: warning: missing terminating \" character\n    6 | printf(\"%d\n      |        ^\na.c:6:8: error: missing terminating \" character\n    6 | printf(\"%d\n      |        ^~~\na.c:7:1: warning: missing terminating \" character\n    7 | \", sum);\n      | ^\na.c:7:1: error: missing terminating \" character\n    7 | \", sum);\n      | ^~~~~~~~\na.c:8:1: error: expected expression before 'return'\n    8 | return 0;\n      | ^~~~~~\na.c:8:10: error: expected ';' before '}' token\n    8 | return 0;\n      |          ^\n      |          ;\n    9 | }\n      | ~         \n",
            "stdout": ""
        },
        "fileError": [
            {
                "name": "a",
                "type": "CopyOutOpen",
                "message": "open a: no such file or directory"
            }
        ]
    }
]

当去掉prinf中的\n中系统又可以正常返回了
这是什么原因

[21mw12]

具体现象就像是prinf中没有输入反引号是一样的，如：

#include <stdio.h>

int main() {
    printf("Hello, World!\n);
    return 0;
}

[criyle]

按照 JSON 的字符串标准，您应当转译字符串中出现的反斜线 \ 为 \\ 那么 \n 应当为 \\n

[21mw12]

非常感谢，我是使用Java去发起请求，还需要再次转义就是\\n