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valid-parantheses.ts
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valid-parantheses.ts
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// Given a string s containing just the characters '(', ')', '{', '}', '[' and ']', determine if the input string is valid.
// An input string is valid if:
// Open brackets must be closed by the same type of brackets.
// Open brackets must be closed in the correct order.
// Every close bracket has a corresponding open bracket of the same type.
// Example 1:
// Input: s = "()"
// Output: true
// Example 2:
// Input: s = "()[]{}"
// Output: true
// Example 3:
// Input: s = "(]"
// Output: false
// Constraints:
// 1 <= s.length <= 104
// s consists of parentheses only '()[]{}'.
//Solution 1 : MY BEST SOLUTION
function isValid(s: string): boolean {
const stack: string[] = [];
for (const char of s) {
if (char === '(' || char === '[' || char === '{') {
stack.push(char);
} else {
const top = stack.pop();
if (!top || (char === ')' && top !== '(') || (char === ']' && top !== '[') || (char === '}' && top !== '{')) {
return false;
}
}
}
return stack.length === 0;
}
//Solution 2 : WEAK PERFORMANCE AND COMPLEX(TRASH) SYNTAX
function isValid(s: string) {
let status = false;
for (let i = 0; i < s.length; i++) {
if (s[i] === "{" && s[i + 1] === "}") {
status = true;
}
if (s[i] === "{" && s[i + 1] !== "}") {
status = false;
}
if (s[i] === "[" && s[i + 1] === "]") {
status = true;
}
if (s[i] === "[" && s[i + 1] !== "]") {
status = false;
}
if (s[i] === "(" && s[i + 1] === ")") {
status = true;
}
if (s[i] === "(" && s[i + 1] !== ")") {
status = false;
}
}
return status;
}
console.log(isValid("()("));