Two Joggers.rb

=begin	

Two Joggers

Description

Bob and Charles are meeting for their weekly jogging tour. They both start
 at the same spot called "Start" and they each run a different lap, which 
 may (or may not) vary in length. Since they know each other for a long time 
 already, they both run at the exact same speed.

Illustration

Example where Charles (dashed line) runs a shorter lap than Bob:

Example laps

Task

Your job is to complete the function nbrOfLaps(x, y) that, given the length 
of the laps for Bob and Charles, finds the number of laps that each jogger 
has to complete before they meet each other again, at the same time, at the start.

The function takes two arguments:

The length of Bob's lap (larger than 0)
The length of Charles' lap (larger than 0)

The function should return an array (Tuple<int, int> in C#) containing exactly
 two numbers:

The first number is the number of laps that Bob has to run
The second number is the number of laps that Charles has to run

Examples:

nbr_of_laps(5, 3) # returns [3,5]
nbr_of_laps(4, 6); # returns [3, 2]

#alternative solution: (not mine)

this solution uses least common multiple from Ruby's library

def nbr_of_laps(x, y)
  lcm = x.lcm(y)
  [lcm/x, lcm/y]
end
	
=end

#my solution

def nbr_of_laps(x, y)
  	result = []
	
	for number in (1..10000)
		if (x * number) % y == 0 
			result[0] = number	
			result[1] = (x * number) / y 
			break
		end
	end
	result
end