-
Notifications
You must be signed in to change notification settings - Fork 1
/
Palindrome_number_leetcode.py
46 lines (34 loc) · 1.09 KB
/
Palindrome_number_leetcode.py
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
"""
Given an integer x, return true if x is palindrome integer.
An integer is a palindrome when it reads the same backward as forward.
For example, 121 is a palindrome while 123 is not.
Example 1:
Input: x = 121
Output: true
Explanation: 121 reads as 121 from left to right and from right to left.
Example 2:
Input: x = -121
Output: false
Explanation: From left to right, it reads -121. From right to left, it becomes 121-. Therefore it is not a palindrome.
Example 3:
Input: x = 10
Output: false
Explanation: Reads 01 from right to left. Therefore it is not a palindrome.
"""
class Solution:
def isPalindrome(self, x: int) -> bool:
if x < 0:
return False
if (x != 0 and x%10 == 0):
return False
# for even numbers
reverse=0
while (x>reverse):
reverse = reverse*10 + x%10
x = x //10
if (x==reverse):
return True
# for odd numbers:
if (x == reverse//10):
return True
return False