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Main.java
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Main.java
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package com.liaoguoyin.pat.团体程序设计天梯赛.L1050;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
/**
* L1-050 倒数第N个字符串 (15 分)
* <p>
* 看了吃猪皮老哥的解析确信是进制数的感觉:
* 题目要求的倒数第 N 个,其实就是L位的26进制数的第 26^L-N 个
*/
public class Main {
public static void main(String[] args) throws IOException {
BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
String tmp = bufferedReader.readLine();
int L = Integer.parseInt(tmp.split(" ")[0]);
int N = Integer.parseInt(tmp.split(" ")[1]);
// 计算对应的正向顺序N
N = (int) Math.pow(26, L) - N;
int[] ints = new int[L];
// 取余,得每一位的值
for (int i = 0; i < ints.length; i++) {
ints[i] = N % 26;
N = N / 26;
}
// 生成字符串
StringBuilder stringBuilder = new StringBuilder();
//System.out.println(Arrays.toString(ints));
for (int anInt : ints) {
char tmpint = (char) ('a' + anInt);
stringBuilder.append(tmpint);
}
// 因为数组序列是从最后一位处理的,所以最后要反转字符串
stringBuilder.reverse();
System.out.println(stringBuilder.toString());
}
}