https://leetcode-cn.com/problems/ransom-note/
Given two strings ransomNote and magazine, return true if ransomNote can be constructed from magazine and false otherwise.
Each letter in magazine can only be used once in ransomNote.
Example 1:
Input: ransomNote = "a", magazine = "b"
Output: false
Example 2:
Input: ransomNote = "aa", magazine = "ab"
Output: false
Example 3:
Input: ransomNote = "aa", magazine = "aab"
Output: true
Constraints:
1 <= ransomNote.length, magazine.length <= 10^5
ransomNote and magazine consist of lowercase English letters.
class Solution:
def canConstruct(self, ransomNote: str, magazine: str) -> bool:
note_dict=Counter(ransomNote)
maga_dict=Counter(magazine)
for k,v in note_dict.items():
if k not in maga_dict.keys() or maga_dict[k]<v:
return False
return True
class Solution:
def canConstruct(self, ransomNote: str, magazine: str) -> bool:
note_dict=defaultdict(int)
for i in ransomNote:
note_dict[i]+=1
maga_dict=defaultdict(int)
for i in magazine:
maga_dict[i]+=1
for i in ransomNote:
if i not in maga_dict or note_dict[i]>maga_dict[i]:
return False
return True