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<a class="article-title" href="/2022/12/21/%E9%A2%98%E7%9B%AE10/">题目10</a>
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<p>已知函数$f(x)=x(e^{\sin x}-\ln{}{x})-1$,试研究$g(x)=f(x)+1$的零点个数</p>
<a class="article-more-a" href="/2022/12/21/%E9%A2%98%E7%9B%AE10/#more">阅读更多 >></a>
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<a class="article-title" href="/2022/12/20/%E9%A2%98%E7%9B%AE9/">题目9</a>
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<p>已知正数$x$,$y$满足$3x-5y=4x^2y^2$,求$\frac{1}{x}+\frac{1}{y}$的最小值。</p>
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<p>已知函数$f(x) = 2e^x + \sin x - 2(x \ge 0)$<br>(1)求$f(x)$的单调区间与零点。<br>(2)若$e^x + \ln_{}{(x+1)} - 1 \ge af(x)$恒成立,求实数$a$的取值范围。</p>
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<article id="post-Image-Super-Resolution-Using-Very-Deep-Residual-Channel-Attention-Networks" class="article article-type-post article-index" itemscope itemprop="blogPost">
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<a class="article-title" href="/2022/11/29/Image-Super-Resolution-Using-Very-Deep-Residual-Channel-Attention-Networks/">论文阅读:Image Super-Resolution Using Very Deep Residual Channel Attention Networks</a>
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<h2 id="一、论文背景及创新点"><a href="#一、论文背景及创新点" class="headerlink" title="一、论文背景及创新点"></a>一、论文背景及创新点</h2><p>首先是<a href="https://arxiv.org/abs/1807.02758" target="_blank" rel="noopener">论文下载地址</a>,以及作者提供的源码<a href="https://github.com/yulunzhang/RCAN" target="_blank" rel="noopener">GitHub仓库</a></p>
<p>在论文中,作者注意到以下两个事实:<br><font color=HotPink>(1)</font> 卷积神经网络的深度是决定超分性能的关键因素,但较深的网络很难训练。<br><font color=HotPink>(2)</font> 低分辨率的输入和特征包含丰富的低频信息,这些信息在各个通道间被同等对待是不合理的,从而阻碍了CNN的表达能力</p>
<p>这里说一下低频信息的概念,低频信息指的是图像缓慢变化的部分。通俗讲,图像中边缘部分变化较大,称为高频信息。而边缘以内的部分缓慢变化,就称作低频信息。</p>
<p>于是作者提出了一种非常深的<font color=MediumPurple>"RCAN"</font>网络,用于超分问题,网络中比较值得关注的部分有两个:<br><font color=HotPink>(1)</font> 提出了RIR(residual in residual)结构,用来构建非常深的能有效训练的网络。<br><font color=HotPink>(2)</font> 提出了一种注意力机制(CA),通过考虑通道间的相互依赖关系,自适应地重新调整通道特征。</p>
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<p>这是一个抓老鼠问题:<br>现在有五个盒子(编号1-5)水平排列,有一只老鼠生活在其中一个盒子里。这只老鼠每天必定会更换一个盒子生活,且只会换到相邻的盒子内。</p>
<p>你每天可以打开其中一个盒子查看,如果盒子中有老鼠,则可以立刻抓住老鼠。如果盒子中没有老鼠,你必须立刻关闭盒子。<br><font color=MediumPurple>假设老鼠足够聪明,且可以预知你的操作。</font><br>问:是否有必定抓到老鼠的策略?试给出你的方案</p>
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<p>已知非零实数$x,y$满足$\frac{x}{y} + \frac{y}{x} + 2xy = x^{2} - y^{2}$,求$x^{2} + y^{2}$的最小值。</p>
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<p>已知$m$和$n$均为质数,且满足$5m+7n=129$,求符合条件的所有$m$和$n$。</p>
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<p>连接正$n$边形$(n\ge 4)$的中心与各个顶点形成$n$个全等三角形,用最多$n-2$种颜色为各三角形染色,要求两个相邻的三角形不能同色,记共有涂色方法$R_{n}$种,证明:<br>$$R_{n} = (n-3)^{n} + (-1)^{n-2} (n-3)$$</p>
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<p>对于动漫来说,怎样才算一个好的bgm?<br>我觉得代入感是很重要的一个评价标准。<br>刀剑神域三季动漫包括一系列剧场版的bgm均由<font face="KaiTi" size=4><strong>梶</strong></font>浦由<font face="KaiTi" size=4><strong>記</strong></font>创作,其中有很多bgm,只要听到,脑海中立刻就会浮现出对应的画面,让人画面感重重。</p>
<p>本文来盘点一下涉及到<font face="KaiTi" size=4><strong>梶</strong></font>浦语的bgm,主要是各个角色的主题曲。</p>
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