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array.ts
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array.ts
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/**
* Return the last index in the array that matches the predicate
*/
export function findLastIndex<T>(array: T[], predicate: (value: T) => boolean): number {
let i = array.length;
while (i--) {
if (predicate(array[i])) {
return i;
}
}
return -1;
}
/**
* The node for LinkedList below
*/
class Node<T> {
data: T;
next: Node<T> | null = null;
prev: Node<T> | null = null;
constructor(data: T) {
this.data = data;
}
}
/**
* We want to use this if we only need push/pop/shift method
* without random access.
* The shift() method should be cheaper than regular array.
*/
export class LinkedList<T> {
private _length: number;
private head: Node<T> | null;
private tail: Node<T> | null;
constructor() {
this._length = 0;
this.head = null;
this.tail = null;
}
get length(): number {
return this._length;
}
push(data: T): void {
if (this._length === 0) {
this.tail = this.head = new Node(data);
this._length++;
return;
}
if (!this.head || !this.tail) {
// should not happen
throw Error("No head or tail");
}
const newTail = new Node(data);
this.tail.next = newTail;
newTail.prev = this.tail;
this.tail = newTail;
this._length++;
}
pop(): T | null {
const oldTail = this.tail;
if (!oldTail) return null;
this._length = Math.max(0, this._length - 1);
if (this._length === 0) {
this.head = this.tail = null;
} else {
this.tail = oldTail.prev;
if (this.tail) this.tail.next = null;
oldTail.prev = oldTail.next = null;
}
return oldTail.data;
}
shift(): T | null {
const oldHead = this.head;
if (!oldHead) return null;
this._length = Math.max(0, this._length - 1);
if (this._length === 0) {
this.head = this.tail = null;
} else {
this.head = oldHead.next;
if (this.head) this.head.prev = null;
oldHead.prev = oldHead.next = null;
}
return oldHead.data;
}
clear(): void {
this.head = this.tail = null;
this._length = 0;
}
toArray(): T[] {
let node = this.head;
if (!node) return [];
const arr: T[] = [];
while (node) {
arr.push(node.data);
node = node.next;
}
return arr;
}
map<U>(fn: (t: T) => U): U[] {
let node = this.head;
if (!node) return [];
const arr: U[] = [];
while (node) {
arr.push(fn(node.data));
node = node.next;
}
return arr;
}
}